Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Answer:
class Solution {
public:
int minPathSum(vector<vector<int> > &grid) {
int m=grid.size();
int n=grid[0].size();
if(m==0||n==0) return -1;
int dp[m][n];
memset(dp,0,sizeof(dp));
dp[0][0]=grid[0][0];
for(int i=1;i<m;++i){
dp[i][0]=dp[i-1][0]+grid[i][0];
}
for(int j=1;j<n;++j){
dp[0][j]=dp[0][j-1]+grid[0][j];
}
for(int i=1;i<m;++i){
for(int j=1;j<n;++j){
dp[i][j]=grid[i][j]+min(dp[i-1][j],dp[i][j-1]);
}
}
return dp[m-1][n-1];
}
};
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