Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Answer:
class Solution {
public:
bool hasPathSum(TreeNode *root, int sum) {
if(!root)return false;
else if(!root->left&&!root->right&&root->val==sum) return true;
else{
if(hasPathSum(root->left,sum-root->val)||hasPathSum(root->right,sum-root->val)){
return true;
}
else
return false;
}
}
};
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