Maximal rectangle -- Leetcode

Answer:

int maximalRectangle2(char[][] matrix) {
 2         int m = matrix.length;
 3         int n = m == 0 ? 0 : matrix[0].length;
 4         int height[][] = new int[m][n + 1];
 5         
 9         int maxArea = 0;
10         for(int i = 0; i < m; i++){
11             for(int j = 0; j < n; j++) {
12                 if(matrix[i][j] == '0'){
13                     height[i][j] = 0;
14                 }

                   else {
15                     height[i][j] = i == 0 ? 1 : height[i - 1][j] + 1;
16                 }
17             }

               int area = maxAreaInHist(height[i]);
21             if(area > maxArea){
22                 maxArea = area;
23             }
           }
25         return maxArea;
26      }